admin管理员组

文章数量:1641904

获取MySQL的表中每个userid最后一条记录的方法,并且针对userid不唯一的情况,需要的朋友可以参考下

表结构

CREATE TABLE `t1` (

`userid` int(11) DEFAULT NULL,

`atime` datetime DEFAULT NULL,

KEY `idx_userid` (`userid`)

) ENGINE=InnoDB DEFAULT CHARSET=utf8;

表数据:

MySQL> select * from t1;

+--------+---------------------+

| userid | atime |

+--------+---------------------+

| 1 | 2013-08-12 11:05:25 |

| 2 | 2013-08-12 11:05:29 |

| 3 | 2013-08-12 11:05:32 |

| 5 | 2013-08-12 11:05:34 |

| 1 | 2013-08-12 11:05:40 |

| 2 | 2013-08-12 11:05:43 |

| 3 | 2013-08-12 11:05:48 |

| 5 | 2013-08-12 11:06:03 |

+--------+---------------------+

8 rows in set (0.00 sec)

其中userid不唯一,要求取表中每个userid对应的时间离现在最近的一条记录.初看到一个这条件一般都会想到借用临时表及添加主建借助于join操作之类的.

给一个简方法:

MySQL> select userid,substring_index(group_concat(atime order by atime desc),",",1) as atime from t1 group by userid;

+--------+---------------------+

| userid | atime |

+--------+---------------------+

| 1 | 2013-08-12 11:05:40 |

| 2 | 2013-08-12 11:05:43 |

| 3 | 2013-08-12 11:05:48 |

| 5 | 2013-08-12 11:06:03 |

+--------+---------------------+

4 rows in set (0.03 sec)

本文标签: 数据mysql