admin管理员组文章数量:1531907
2023年12月13日发(作者:)
口袋妖怪java_简单的Java口袋妖怪扑灭模拟器
我已经写了一个类创建和战斗口袋妖怪,但我不知道如何调用测试类中的战斗方法,以测试我写的类。简单的Java口袋妖怪扑灭模拟器
我的任务是编写和测试模拟两个口袋妖怪之间的战斗模拟。每个口袋妖怪都有一个健康值,一个强度值和一个速度值。健康值,强度值和速
度值作为参数传递给构造函数。这些值最初必须介于1和300之间,最初应该为非零值。完成游戏的总体思路是,两个口袋妖怪将在模拟中
与另一个“战斗”,口袋妖怪轮流攻击。 (具有最高速度值的那一个每轮首先进行)攻击口袋妖怪的力量将从“攻击者”身体中减去。
public class Pokemon{
private int health;
private int strength;
private int speed;
/**
* Constructs the pokemon
* @Require:
* health is an integer greater than or equal to 1 but less than or equal to 300
* strength is and integer greater than or equal to 1 but less than or equal to 300
* speed is an integer greater than or equal to 1 but less than or equal to 300
*/
public Pokemon(int health, int strength, int speed){
assert health >= 1;
assert health <= 300;
assert strength >= 1;
assert strength <= 300;
assert speed >= 1;
assert speed <= 300;
= health;
th = strength;
= speed;
}
public void battle(Pokemon pokemon1, Pokemon pokemon2){
do{
n(pokemon1+" begins the fight against "+pokemon2);
= - th;
n(pokemon1 +" does "+ th +" damage to "+
pokemon2 +" and "+ pokemon2 +" has "+ +" left.");
= - th;n(pokemon2 +" does "+ th +" damage to "+
pokemon1 +" and "+ pokemon1 +" has "+ +" left.");
}while( >= 1 || >= 1);
if( < 1)
n(pokemon1 +" has lost the fight");
else
n(pokemon2 +" has lost the fight");
}
}
口袋妖怪仪
public class PokemonTester{
private Pokemon charizard;
private Pokemon blastoise;
private Pokemon venusaur;
public PokemonTester(){
charizard = new Pokemon(100,50,50);
blastoise = new Pokemon(150,25,150);
venusaur = new Pokemon(300,10,100);
}
public static void main(String[] args){
(charizard, blastoise); //will not compile
}
}
我意识到我还没有实现在服用速度方面还转,因为我想只是使它工作。
2011-10-29
Brian
+1
请注意,你的while可能不是你想要的:只要一个口袋妖怪的健康<= 0,while循环应该停止。因此,你需要一个'while > = 1
&& > = 1'注意'&&'而不是'||' –
+2
从现在开始,我将使用口袋妖怪名称作为变元变量。 –
+0
@Inerdia我同意这比真正的动物编程101锻炼更有趣 - 嘿,谁想看到狗与猫战斗? ;) –
版权声明:本文标题:口袋妖怪java_简单的Java口袋妖怪扑灭模拟器 内容由热心网友自发贡献,该文观点仅代表作者本人, 转载请联系作者并注明出处:https://m.elefans.com/dongtai/1702401947a5146.html, 本站仅提供信息存储空间服务,不拥有所有权,不承担相关法律责任。如发现本站有涉嫌抄袭侵权/违法违规的内容,一经查实,本站将立刻删除。
发表评论